Showing posts with label Separable Differential Equation. Show all posts
Showing posts with label Separable Differential Equation. Show all posts

Monday, October 23, 2017

For the below ordinary differential equation, state the order and determine if the equation is linear or nonlinear. Then find the general solution of the ordinary differential equation. Verify your solution. dy/dx = 2y

Question.

For the below ordinary differential equation, state the order and determine if the equation is linear or nonlinear. Then find the general solution of the ordinary differential equation. Verify your solution.

dy/dx = 2y


Solution:







Friday, October 20, 2017

Solve the separable differential equation dy/dx = -0.8/cos(y) with initial condition y(0) = pi/4

Question.



Solve the separable differential equation dy/dx = -0.8/cos(y) with initial condition y(0) = pi/4


Solution:




Solve the separable differential equation y’ = sqrt(-2y + 41) with initial condition y(-5) = 8

Question.

Solve the separable differential equation y’ = sqrt(-2y + 41) with initial condition y(-5) = 8

Solution:





dy/dx = (1+y^2)/(y+yx^2)

Question.


dy/dx=(1+y^2)/(y+yx2)


Solution:




Saturday, October 14, 2017

Find the explicit solution of the differential equation that satisfies the given initial condition. y dy/dx = xe^(-y^2) , y(0) = -3

Question.

Find the explicit solution of the differential equation that satisfies the given initial condition.
y dy/dx = xe^(-y^2) , y(0) = -3

Solution:






Sunday, July 23, 2017

Find the solution to the following separable differential equation y' = ye^x

Question.

Find the solution to the following separable differential equation.
y’ = yex

Solution:




Sunday, July 9, 2017

Solve the separable Differential Equation dy/dx = e^(3x+4y)

Question. Solve the separable Differential Equation dy/dx = e^(3x+4y)


Solution:





Friday, August 7, 2015

dy/dx = 3e^(2x) , y(0) = 5/2



dy/dx = 3x^2 y^2 - y^2

Find the general solution to the differential equation
dy/dx = 3x^2 y^2 - y^2
Find the particular solution for which y(0) = 1 ie when x = 0 , y =1


Tuesday, August 4, 2015

dy/dx = 1/(x^2 - 3x) , y(4) = (2/3) ln(4)

Solve the initial value problem and give the interval of definition.
dy/dx = 1/(x^2 - 3x) , y(4) = (2/3) ln(4)






dy/dx= xy + 7x +2y + 14

dy/dx= xy + 7x +2y + 14