Showing posts with label Inverse Laplace Transform. Show all posts
Showing posts with label Inverse Laplace Transform. Show all posts

Saturday, February 17, 2018

Solve differential equation using Laplace Transforms. y'' - 6y' + 5y = te^t , y(0) = 2 , y'(0) = -1

Question.


Solve differential equation using Laplace Transforms.

y'' - 6y' + 5y = te^t , y(0) = 2 , y'(0) = -1

Solution:


Solve by using Laplace Transforms. y'''' - 9y = 0 , y(0) = 1, y'(0) = 0 , y''(0) = 0 , y'''(0) = 1

Question. Solve by using Laplace Transforms.
y'''' - 9y = 0 , y(0) = 1, y'(0) = 0 , y''(0) = 0 , y'''(0) = 1

Solution:

Thursday, January 18, 2018

Monday, October 23, 2017

Monday, October 16, 2017

Find the inverse Laplace transforms of the functions given below (A) s/(s^2 + 6s + 18) ; (B) 10/(s^2 + 10s + 34)

Question.

Find the inverse Laplace transforms of the functions given below
A) s/(s2+6s+18)
B) 10/(s2+10s+34)


Solution:



Sunday, July 9, 2017

Use the Laplace transform to solve the given initial value problem y'' - 2y' + 2y = e^(-t) , y(0)=0 , y'(0)=1

Question. Use the Laplace transform to solve the given initial value problem 
y'' - 2y' + 2y = e^(-t) , y(0)=0 , y'(0)=1

Solution:



Use the Laplace transform to solve the given initial value problem: y''+2y'+5y=0 , y(0) = 2 , y'(0) = -1

Question. Use the Laplace transform to solve the given initial value problem:
y''+2y'+5y=0 ,  y(0) = 2 , y'(0) = -1


 Solution:





find the inverse Laplace transform of F(s) = e^(-3s)/((s - 1)(s + 3))

Question. find the inverse Laplace transform of F(s) = e^(-3s)/((s - 1)(s + 3))

Solution:



Find the inverse Laplace transform of F(s) = e^(-5s)/(s^2 - 2s + 2)

Question. Find the inverse Laplace transform of F(s) = e^(-5s)/(s^2 - 2s + 2)

Solution:




Saturday, February 6, 2016

Laplace Transform Initial Value Problem y' + 4y = f(t), y(0) = 0, where f(t) = {t, 0 <= t < 1 0, t >= 1}

Use the Laplace transform to solve the given initial-value problem. y' + 4y = f(t), y(0) = 0, where f(t) = {t, 0 <= t < 1 0, t >= 1}






Friday, January 29, 2016

Sunday, August 9, 2015

Tuesday, August 4, 2015