Sunday, November 13, 2016

Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0. y'' + 2y' - 8y = 6e^(-2x) - e^(-x)

Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0.


y'' + 2y' - 8y = 6e^-2x - e^-x




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